There are approximately

First we need to find the original gravity:

Alcohol(by weight) = 76.08(OG-FG)/(1.775-OG)

7.5 = 76.08(x - 1.012) / (1.775 - x)

7.5(1.775 - x) = 76.08(x - 1.012)

13.3125 - 7.5x = 76.08x - 76.99

90.3025 = 83.58x

x = 1.080

OG = 1.080

Now, for the calories calculation:

C = 851(1.080 - 1)(1.080 + 3)

C = 851 * 0.080 * 4.080

C = 277.77

Christmas Ale 2010 = ???

Christmas Ale 2009 = 313.25

Christmas Ale 2008 = 242.45

**278 calories in each 12 fluid ounces of Great Lakes Christmas Ale**this year, if my math is correct. Below are my calculations, if you would like to know how I came to this answer. To calculate the number on your own: grab a hydrometer, calculate the final gravity, plug your findings into the equations below, and let me know if I did it right!First we need to find the original gravity:

Alcohol(by weight) = 76.08(OG-FG)/(1.775-OG)

7.5 = 76.08(x - 1.012) / (1.775 - x)

7.5(1.775 - x) = 76.08(x - 1.012)

13.3125 - 7.5x = 76.08x - 76.99

90.3025 = 83.58x

x = 1.080

OG = 1.080

Now, for the calories calculation:

C = 851(1.080 - 1)(1.080 + 3)

C = 851 * 0.080 * 4.080

C = 277.77

**Historical Values:**Christmas Ale 2010 = ???

Christmas Ale 2009 = 313.25

Christmas Ale 2008 = 242.45